2log(x - 3) = 1 + log(x) + log(2) - log(5)
log(x - 3)² - log(x) - log(2) + log(5) = 1 (multiplier goes inside as an exponent)
log[ 5(x - 3)² / (2x) ] = 1 (subtraction ---> division; addition ---> multiplication)
5(x - 3)² / (2x) = 10 (raise both sides as exponents upon 10)
(x - 3)² / (2x) = 2 (divide by 5)
(x - 3)² = 4x (multiply by 2x)
x² - 6x + 9 = 4x (multiply out)
x² - 10x + 9 = 0
(x - 9)(x - 1) = 0
x = 9 <---- answer x = 1 <--- won't check