geno3141

sin(angle of incidence) / sin(angle of refraction)  =  1.33

--->  sin( 30 ) / sin ( X ) = 1.33

--->  sin( 30 )  =  1.33 x sin( X )

--->  sin( 30 ) / 1.33  =  sin( X )

--->  0.665  =  sin( X)

--->  X  =  invSin( 0.665 )

--->  X  =  41.7°

You will need to be smore specific because there are an infinite number of coordinates that fit into that formula.

For instance, do you want the x-intercept or the y-intercept or ???

I have only restricted knowledge of physics, but let me try:

Gravitational Force  =  G * m1 * m2 / d²

where G is the constant 6.673 x 10^-11 Newton-meters² / kilograms²

m1 and m2 are the two masses, in kilograms

d is the distance between the centers of the masses, in meters

For this problem:  GF  =  (6.673 x 10^-11 N-m/kg²) x (16 kg) X (34 kg) / (1.6 m)²

                    GF  =  1.4 x 10^-8 Newtons 

In a triangle whose angles are A, B, and C and whose opposite sides are a, b, and c, the Law of Sines can be

written as:     sin(A) / a  =  sin(B) / b  =  sin(C) / c          or as          a / sin(A)  =  b / sin(B)  =  c / sin(C)

If the unknown is an angle, use the formula on the left; if the unknown is a side, use the formula on the right     because an equation is easier to solve if the unknown is in the numerator.

In either case, you don't use the whole equation at one time, just the fraction that contains the unknown and the fraction that contains the two parts (angle and side) that you know.

The slope-intercept form of a line is:  y = mx + b, where m represents the slope and b represents the y-intercept.

For the line   y = 2/3x - 4,  the slope is  2/3.

Any line perpendicular to that line has a slope that is the negative reciprocal of that slope.

The negative reciprocal of  2/3  is  -3/2.

To find the new equation, start with  y = mx + b.

Its slope is  -3/2  and because it passes through the point  (-5, 6) one of its x-values is  -5  and one of its y-values is  6.  Place these values into  y = mx + b:

                                                      6  =  (-3/2)(-5) + b  

Now, solve for b:                             6  =  15/2  +  b  --->   6  =  7.5 + b  -->  b  = -1.5

Place  m = -3/2  and  b = -1.5  into the slope-intercept form to get:  y  =  -3/2x + -1.5

Simplifying:  y  =  -1.5x - 1.5

It doesn't have a horizontal phase shift because a cos graph starts at a maximum at 0 and goes downward to the right.

You have a right triangle and you want to find the size of the angle that is formed by the 7' length and the 21' length. The 7' length is adjacent to the angle while the 21' length is the hypotenuse of the triangle.

Since you have the adjacent side and the hypotenuse, use the cosine because  cos = adj/hyp

cos X  =  7/21    --->   X = invCos (7/21)

Do you want to solve it, as an equation?  2p - 26  = 0

Or, do you want to factor it?

Make certain that your calculator is in degree mode.

To solve a tangent problem, use invTan  or (2nd) tan

tan θ  =  -4        --->        θ   =  invTan( -4 )        --->         θ  =  -76.0°

But this answer isn't in your range of values.

However, tan has a period of 180°, so you can add or subtract 180° as many times as you like:

adding 180° to -76.0°, the answer becomes 104°.

I hope this helps!

[ (30 * 1000) + (3x100) - (90 + 1028) ] * 3

Work from the inside out:

[ (30000) + (300) - (1118) ] * 3

Finish the inside:

[ 29182 ] * 3

  =  87546