geno3141

It has an infinite number of multiples:

1 x 200 = 200

2 x 200 = 400

3 x 200 = 600

etc.

Did you mean factors?

Sorry, I should have ended with:   x² ( x - 1 ).

x³ - x²  can't be simplified as a subbtraction problem.

However, if you want to factor it, you can:  

Both  x³  and  x²  contain an  x², so factor out the x²  to end with  x³ ( x - 1 ).

To simplify this, combine the  k-terms  to get only one  k-term  and combine the numbers to end with only one number:

3k - 2k  =  1k, or just k

-12 + 2  =  -10

Answer:  k - 10

In the expression    100 - 30 ÷ 5     if you follow the rules of operations, you have to do all divisions before you do subtractions, so    100 - 30 ÷ 5     becomes    100 - 6     which is  94.

0.5625  =  5625 / 10000  

   =  1125 / 2000               (divide by 5)

   =  225 / 400                   (divide by 5)

   =  45 / 80                       (divide by 5)

   =  9 / 16                         (divide by 5)

(-4·u³·w)³  =  (-4)³·(u³)³·(w)³  =  -64u^9w³

If  tan(x) = 2, the x = 63.435°.

cos(2x) = cos(2·63.435°) = cos(126.870°) = -0.6

This can also be done without a calculator, if you need that explanation, please repost.

This graph will have a dashed line because it is an inequality without the equal sign.

If it were  ≤  or  ≥  then the line would be solid.

To find where the line should be drawn, find these two points:  ( 0, y )  and  ( x, 0 )

To find the point  ( 0, y )  replace  0  for  x  in the equality:  5x - 2y  =  10.

     Putting in  0  for  x  and solving,  y  =  -5     --->     ( 0, -5 )

To find the point  ( x, 0 )  replace  0  for  y  in the equality:  5x - 2y  =  10.

     Putting in  0  for  y  and solving,  x  =  2     --->     ( 2, 0 )

Place those two points on the graph and draw a dashed line through those points.

Now, you will have to shade one side of the line; either above or below. Chose any point which is clearly one on side or the other.

The point  ( 0, 0 ) is easy to use and is clearly above the line, so test ( 0, 0 ) in the inequality 5x - 2y  >  10.

If the point makes the equation true, then shade the side that the point is on; if the point does not make the equation true, then shade the opposite side.

Putting ( 0, 0 )  into  5x - 2y  >  10  you get  5(0) - 2(0) > 10  which is  0 > 10 which is clearly false.

Thus, graph the opposite side, the side that doesn't contain this point; graph the region below the line.