geno3141

If you have  15  choices, you will get  15!  answers; however, since some of the choices are repeated, this answer must be divided by the number of ways that they can be repeated.

The  A's  has be repeated  2!  ways.

The  C's  can be repeated  4!  ways.

The  G's  can be repeated  4!  ways.

The  T's  can be repeated  5!  ways. 

Thus, your answer will be:     15! / ( 2! x 4! x 4! x 5! )

Let the price of a ticket be  x.

Since you bought 5 tickets, the total cost for all five tickets is  5x.

The convenience charge is  2.50 per ticket, and since there are 5 tickets, this will be  2.50·5.

To this you have to add  15  for ruh delivery.

Equation:     5x +  2.50·5  +  15.00  =  352.50

                   5x  +  12.50  +  15.00  =  352.50

                                  5x  +  27.50  =  352.50

                                                 5x  =  325.00

                                                   x  =  $65.00  

3 / 24  is  3  divided by  24:  0.125

If we write each of these as a power of 3, we can show that the left side equals the right side.

Left side:

1 / 27  =  1 / 3^3  =  3^-3

9^24  =  (3²)^24  =  3^48                   (When you have an exponent to an exponent, multiply the exponents.)

(3^-3) x (3^48)  =  3^45                     (When you multiply numbers with the same base, add the exponents.)

Right side:

27^15  =  (3^3)^15  =  3^45

You will need to know the approximate miles per gallon of that car and the cost per gallon of the gas.

You can calculate the cost by taking the (number of miles you want to travel) and dividing this by the (number of miles per gallon that you get in your car) and multiplying that answer by the (cost per gallon of gas).

For instance, if you want to travel 310 miles and you car gets 28 miles per gallon and gas cost $3.10 per gallon, the calculation is:  310 ÷ 28 x 3.10  =  $34.32 (approximately).

You can graph these sets of values. For this type of problem, you don't actually have to graph them, just realize that if you had the equation of the graph of the line that went through those values, that would be your answer.

If you know at least two points on a line, you can find the equation of that line using the point-slope form.

Point-slope form:  y - y1  =  m( x - x1)

But this will require that you know the slope; you can find the slope by:  m  =  (y2 - y1) / (x2 - x1)

Top problem:  first find the slope:  x1 = 1  y1 = 24    x2 = 2  y2 = 48

    m  =  ( 48 - 24 ) / ( 2 - 1 )     --->     m  =  2

Placing the values of  m,  x1  and  y1  into the point-slope form:  y - 24  =  24( x - 1 )

and reducing the equation:  y - 24  =  24x - 24     --->   y  =  24x.

Bottom problem:  x1 = 1     y1 = .60     x2 = 2     y2  = .70

    m  =  ( .70 - .60 ) / ( 2 - 1 )     --->     m  =  .10

Placing the values of  m,  x1  and  y1  into the point-slope form:  y - .60  =  .10( x - 1 )

and reducing the equation:  y - .60  =  .10x - .10     --->   y  =  .10x + .50.

(These can also be done without graphing formulas; if you would prefer that way, post back.)

Let the two numbers be  x  and  y.

Then, we have:         x · y  =  121          and         x + y  = 3/2

Since:  xy  =  121,  then, solving for x:  y  =  121 / x

Substituting this value of  x  into the equation  x + y  =  3 /2 ,  we get:   x + 121/x  =  3/2.

Multiplying both sides of this equation by  x:  x² + 121  =  3/2x

Multiplying both sides by 2:  2x² + 242  =  3x

Rewriting into quadratic form:  2x² - 3x + 242  =  0

Using the quadratic formual with  a = 2,  b = -3,  and c = 242,  we get:  ( 3 ± √( 9 - 4(2)(242) ) ) / 4

These two answers are:  ( 3 + √(-1927) ) / 4    and    ( 3 - √(-1927) ) / 4

which become the two possible values for  x  and  y.

4/5 is turned into a decimal fraction by dividing 4 by 5.

4 ÷ 5  =  .8

4 4/5  =  4 + 4/5  =  4 + .8  =  4.8

A z-score will be negative for a score that is lower than the average score.

Basically, it can't be done.

Square feet is a measure of area, such as the area of a floor.

Linear feet is a measure of length, such as the length of one side of a floor.

There are some problems, such as how many linear feet of a floor covering does it take to cover the floor, can be answered if the width of each of the floor sections is known. If you have this type of problem, post back with more information.