geno3141

Since you don't have a right triangle, you can't use just sin, cos, or tan

Either use the Law of Cosines (if you have SAS or SSS) or otherwise use the Law of Sines.

Since you don't have either SAS or SSS, use the Law of Sines.

   sin(R) / r  =  sin(Q) / q                           

   sin(R) / 3.5  =  sin(70°) /6.2                       

This is as far as you have to go, but you could finish it:

   sin(R)  =   sin(70°) /6.2 x 3.5

     R  =  invSin(  sin(70°) /6.2 x 3.5 )

4 x 10^3 x 2 x 10^2

Rearrange:  4 x 3 x 10^3 X 10^2

    =    12 x 10^5                   (add exponents when multiplying numbers with the same base)

    =    1.2 x 10^6

Get all the x-terms to one side and all the numbers to the other.

Subtract  7x  from both sides:

8x - 7x + 12  >  7x - 7x + 2

x + 12  >  2

Subtract  12  from both sides:

x + 12 - 12 > 2 - 12

x  >  -10

8  =  1/4·f(-2x)     ===>    32 = f(-2x)    ===>    f(-2x) = 32

This indicates that the function  f(x)  is a constant function; that is, for every value of  x,  the answer is  32.

3c^4·(6c^3 + 7c)    =    3c^4·(6c^3)  +  3c^4·(7c)

                               =  18c^7 + 12c^5

Multiply numbers times numbers and variables times variables. If the bases are the same under multiplication, add the exponents.

Since kj = mj, k = m.

Since lk = nm and k = m, l = n.

If you do it by trial-and-error, there are a lot of possibilities;  

15  can be factored as  (1 and 15)  or  (3 and 5)

32  can be factored as  (1 and 32)  or  (2 and 16)  or  (4 and 8)  or  (8 and 4)  or  (16 and 2)  or  (32 and 1)

Since the last term is positive, the two factors must either be both positive or both negative; since the middle term is negative, they must both be negative.

(n - 1)(15n - 32) =

(n - 2)(15n - 16) =

(n - 4)(15n - 8) =

(n - 8)(15n - 4) =

(n - 16)(15n - 2) =

(n - 32)(15n - 1) =

(3n - 1)(5n - 32) =

(3n - 2)(5n - 16) =

(3n - 4)(5n - 8) =

(3n - 8)(5n - 4) =

(3n - 16)(5n - 2) =

(3n - 32)(5n - 1) =

One of the above is correct, the problem is to determine which of the above has the correct middle term, the O and I of FOIL.

It's there ...

A formula that calculates the sum is:  Sum  =  n(f + l) / 2

where  n  is the number of terms (if you want the sum of 14 terms, n = 14),

f  is the value of the first term, and

l  is the value of the last term (if you want the sum of 14 terms, l is the value of the 14th term.

g - (-16)  =  4                            Since     -(-16)  = +16:

g + 16  =  4                               Subtract 16 from both sides:

g + 16 - 16  =  4 - 16

g  =  -12