Melody

your question does not make sense.

3C2 * 0.6^2 * 0,4 = 3*0.36*0.4 = 0.432

Thanks Builderboi,   

Here ia another approach. 

\(\left(\frac{9}{25}\right)^{-\frac{3}{2}}-\frac{\sqrt x}{27}=\left(\frac{3^3}{11^2}\right )^{-1}\\~\\ \left(\frac{3}{5}\right)^{-3}-\frac{\sqrt x}{27}=\left(\frac{27}{121}\right )^{-1}\\~\\ \left(\frac{5}{3}\right)^{3}-\frac{\sqrt x}{27}=\frac{121}{27}\\~\\ \frac{125}{27}-\frac{\sqrt x}{27}=\frac{121}{27}\\~\\ 125-\sqrt x = 121\\~\\ \sqrt x = 4\\~\\ x=16 \)

That is great.  

I like that you have used a link to Chris's answer.

Just one little suggestion.

Please put the address in the link so that people know where they are linking to.

I, for one, am wary about hyperlinking to unknown destinations.

No, you have misunderstood.  I did not explain myself well.

For most posts, what you did was perfect!

I have hidden the original post because it was a great string of questions and I do not want people to think it is ok to do that.

It is not ok, we are not here to do the entirity of people's homework for them.

That is the only reason I posted the pic, i did not want the original to be visible.

If it had been any normal post then what you did was perfect.

By giving a link you are automatically giving the writer the credit. 

Its ok,

Referring back to old answers is perfectly acceptable. ... usually encouraged.

I was a bit shocked to see how Omi had effectively done someones assignment for them but it was a long time ago.

If I saw a post like that today i would delete it but the individual answers are fine.

I think I will just add the answer, giving Omi credit for it of course. Just in case the assignment has been repeated in its entirity.

Thanks you for finding, and posting it.

If you are saying that one side is 77cm and the diagonal is 85cm then use pythagoras's theorem to find the 3rd side.

(a-bi)^2 = 8 - 6i + 13 - 4i

\((a-bi)^2 = 8 - 6i + 13 - 4i\\ a^2-b^2-2abi=21-10i\\ a^2-b^2=21\qquad and \qquad -2abi=-10i\\ a^2-b^2=21\qquad and \qquad ab=5\\ \)

As just chillin said, there are not integer solution set for this.

Guest, it is only 5 digits and the first one must be 9.

chose 4 digits that are less then 9

8,7,6,5,4,3,2,1,0

9C4=126

I get 126.