Melody

I am sure you are capable of doing something towards the answer.

Let the sides be x, y, z   and see what you come up with.

A certain integer has 4 digits when written in base 8.     Let the mumber be y

8^3=512      8^4=4096

In base 10                                  512 <= y < 4096

The same integer has d digits when written in base 3. What is the sum of all possible values of d?

3^5 = 243       4 digits

3^6 = 729        5 digits

3^7 = 2187      6 digits

3^8 = 6561      too big

so it could have 4, 5 or 6 digits in base 3 

You are right, I did .   Thanks Builderboi! 

Hi Hipie, 

Welcome to Web2.0calc forum :)

Here is a video that explains it well.

Thanks hipie, that question was similar.  (I did give you a point but someone else deducted one, you can give yourself a point though.) 

I just want to play with it myself

14,15,16,17,18,19,

25,26,27,28,29

36,37,38,39,

47,48,49

58,59

These are the acceptable pairs there are  6+5+4+3+2 = 20 of them

9C2=36 possible pairs

P(success)=20/36  = 5/9

 log(ln(log(∫ln(dx(log(f(x+(log(al($3$))))))))))

looks like a nonesense question to me.

AoPS questions are not welcome here.

This question has been closed.

Kakashi, you are being a pest.

This mathematics is way over your head and you know that. 

Thanks for your answer Max.  

It is a rectangle + 2 half circles. 

You can work that out   ;)