La respuesta es -3

Siempre tiene que dar un número entero, y para ello debes dividir el número del numerador y el número del denominador entre el mismo número, para hallar la fracción irreducible.

Por ejemplo:

$${\frac{{\mathtt{125}}}{{\mathtt{25}}}} = {\frac{{\mathtt{25}}}{{\mathtt{5}}}} = {\frac{{\mathtt{5}}}{{\mathtt{1}}}} = {\mathtt{5}}$$

12*12= 12²= 144

La respuesta es 0.4

$${\frac{{\mathtt{1}}}{{\mathtt{4}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{3}}}{{\mathtt{2}}}} = {\frac{{\mathtt{1}}}{{\mathtt{4}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{6}}}{{\mathtt{4}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{5}}}{{\mathtt{4}}}}$$

$$\left({\mathtt{9}}{\mathtt{\,\small\textbf+\,}}{\mathtt{30}}\right){\mathtt{\,\small\textbf+\,}}\left[{\mathtt{4}}{\mathtt{\,-\,}}\left({\mathtt{12}}\right)\right] = {\mathtt{39}}{\mathtt{\,\small\textbf+\,}}\left({\mathtt{4}}{\mathtt{\,-\,}}{\mathtt{12}}\right) = {\mathtt{39}}{\mathtt{\,-\,}}\left({\mathtt{8}}\right) = {\mathtt{39}}{\mathtt{\,-\,}}{\mathtt{8}} = {\mathtt{31}}$$

⁴√0.16= 0.632455

Donde dice Insert y Special Character, allí buscas el 2 pequeñito.

Efectivamente, ya que es redondeo a unidades y si es 5 o más de 5 se le suma 1 al número anterior, es decir 18

√145622 = 381.60

$${\mathtt{3}}{\mathtt{\,\times\,}}\left[{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{6}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}\left(-{\mathtt{5}}\right)\right] = {\mathtt{3}}{\mathtt{\,\times\,}}\left[{\mathtt{12}}{\mathtt{\,-\,}}\left({\mathtt{10}}\right)\right] = {\mathtt{3}}{\mathtt{\,\times\,}}\left({\mathtt{12}}{\mathtt{\,-\,}}{\mathtt{10}}\right) = {\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{2}} = {\mathtt{6}}$$

$$\left(-{\mathtt{1}}\right){\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}\left(-{\mathtt{3}}\right) = \left(-{\mathtt{12}}\right){\mathtt{\,\times\,}}\left(-{\mathtt{3}}\right) = {\mathtt{36}}$$