Post the full question/equations please.
13. You can insert a number for ? to create your own problem such as 1/8 of 16 or 2/8 of 16 or 3/8 of 16.
If it was 1/8 of 16, then you know that every 1 out of 8 boxes would be selected meaning that you get 2.
12 --> 2*2*3 --> 2^2 * 3^1.
What's a partition?
Yes, great work, DS!
Check your answers with http://www.mathsisfun.com/least-common-multiple-tool.html.
Note that you don't need to multiply out to solve for x because you already have two factors.
Yep, well you only need one 1^1 since you want only 1 of each number but it doesn't matter much since it's just 1.
