geno3141

Depending upon the calculator that you are using, use invcos(A) or arccos(A) or cos^-1(A).

For the calculator at this site, press (2nd) (asin), then enter 0.9931...

You can use the proportion:     degrees / 180  =  radians / π

     --->     degrees  =  radians · 180 / π

     --->     radians  =  degrees · π / 180

You can set up a proportion:    75% / 100%  =  15 / 

    --->     .75 / 1.00  =  15 / x

    --->     .75 · x  =  15                (multiply both sides by x)

    --->     x  =  15 / .75                (divide both sides by .75)

    --->     x  =  20 questions   

My understanding is that 'div' gives the quotient for integer division and 'mod' gives the remainder.

So, when 15 is divided by 6, the integer quotient (div) is 2 and the remainder (mod) is 3.

15 div 6 = 2

3 div 6 = 0     (integer quotient is 0, remainder is 3)

If I'm correct, then 20 mod 0 is undefined because division by zero is not allowed.

For me 'minint', or 'min int', is the smallest (therefore, usually negative) integer for a particular computer configuration. This value depends upon whether you have an 8-bit, 16-bit, 32-bit, 256-bit, etc. system.

Additions or corrections, anybody?

(5c - 2c)(d + 4)

Simplify the expression in the first set of parentheses:  5c - 2c  =  3c:

=  3c(d + 4)

Use the distributive property:

=  3c(d) + 3c(4)

=  3cd + 12c

If you want to write a number like  3 5/7 as a mixed number:

multiply the whole number part (3) times the denominator (7):  3 x 7 = 21

and add the numerator (5):  3 x 7 + 5  =  26

Place this over the denominator:  3 5/7  =  26/7

Another example:  5 7/8  =  5 x 8 + 7 =  47 --->  47/8

This question was taken up in great seriousnes by Bertrand Russell and Alfred Lord Whitehead in their magnum opus Principia Mathematica where they attempted to place all of mathematics (at least arithmetic) under logic. They succeeded to prove that 1 + 1 = 2 on page 362. This book is unbelievably difficult to understand.

If you wish, check it out online, Wikipedia will be a good source.

No disagreement with happy7, but if you did not mean that 197 to be the denominator of the exponent but rather you meant this:  (2x10^-10)/197, then the answer would be 1.015 x 10^-12.

Why don't you just enter the problem into a calculator and solve it for yourself?

I believe that, by definition ^-12  =  log₂(⁰2)  =  log₂(1)  =  0.

I would suggest going online to find a fuller explanation. 

-(-2)² - 2(-2)

= -(4) - 2(-2)

= -4 - 2(-2)

= -4 + 4

= 0