geno3141

Distance = Rate x Time

6.4 miles  =  Rate x 4 hours                              Divide both sides by 4 hours:

6.4 miles / 4 hours  =  rate

1.6 miles / hour  =  rate

The line above the  3y - 4x  does matter; it indicates that the  3y - 4x  is to be considered as one group; it means the same thing as if they put parentheses around the  3y - 4x. Putting square parentheses around the 3y - 4x, we get:

5x - [-3x - (-2y + 5x) - (10x - [3y - 4x] ) ] 

Work from the inside parentheses out:                      simplifying the   - [3y - 4x]:

5x - [-3x - (-2y + 5x) - (10x - 3y + 4x) ]                  simplifying the  10x - 3y + 4x:

5x - [-3x - (-2y + 5x) - (14x - 3y) ]                          simplifying the   - (-2y + 5x):

5x - [-3x + 2y - 5x - (14x - 3y) ]                              simplifying the   - (14x - 3y):

5x - [-3x + 2y - 5x -  14x + 3y ]                               simplifying the  -22x + 5y:

5x - [-22x + 5y] 

5x + 22x - 5y

27x - 5y

Suggestion:  factor the numerator; since its last term is positive while the middle term is negative, its factors                        must be (a -   )(a -   )

                   factpr the denominator; since its last term is negative, its factors must be (a +   )(a -   )

                   then cancel like factors.

If you have trouble with the factoring, then post back.

If you meant:  (625a²b - 125ab²) / 25a²b²:

Factor the numerator; a common factor is  125ab:     125ab(5a - b) / 25a²b²

Cancel:  5(5a - b) / ab

It is easier to solve an equation if it has no denominators, the denominator, b, can be eliminated by multiplying each term by 'b', resulting in:

16 - 5b = 3 - 2

16 - 5b = 1                      Subtracting 16:

   -5b = -15                    Now, divide by -5.

A negative exponent on a number or variable in a fraction can be turned into a positive exponent if you move the factor from the numerator to the denominator (or from the denominator to the numerator).

For instance:  y^-3  can be written as  1 / y^3                                (this places the y³ in the numerator)         and  1 / x^-2  can be written as  x^2 / 1  , or simply as x²               (this places the x² in the denominator)   so the problem can be written (with positive exponents only) as:

(5·x²·x²·z) / (y³·y)   =   5x^4z / y^4

Because you are given possible answers, you don't really have to solve the problem; all you need to do is check the answers

The first part of the problems asks you to find the cube root of 64; it is 4 because 4x4x4 = 64. Since only one of the possible answers has 4, you're done.

If you want to simplify a cube root of a variable that has an exponent, divide that exponent by 3                                the cube root of  a^6    is  a^2                                                                                                                    the cube root of  b^15  is  b^5                                                                                                                    the cube root of  c^3    is  c^1  or just c

To find square roots, divide by 2; to find fouth roots, divide by 4, etc.

Fator the numerator:  2E - 4  =  2(E - 2)

Factor the denominator:  8E² - 22E + 12  =  2(4E² - 11E + 6)                                                                                Now, you will need to factor  4E² - 11E + 6  into two factors  (        )(      );                                                      the only factor that you have to try is  (E - 2)  because nothing else will cancel the factor in the                          numerator.        Factoring  4E² - 11E + 6  =  (E - 2)(4E - 3)

In factored form:  [ 2(E - 2) ] / [ 2(E - 2)(4E - 3) ]  =  1 / (4E - 3)

Divide the number by the number:  -96 / -24  =  4

Divide the w-terms:  W^4 / W^2  =  W^2                  (subtract exponents)

Divide the L-terms:  L^8 / L^6  =  L^2                      (subtract exponents)

Divide the M-terms:  M^2 / M^2  =  1                       (they cancel)

Multiply the individual parts together:  4W²L²

A mid-value can be negative:  for instance the mid-value between -6  and  2  is  ( -6 + 2 ) / 2  =  -2.

The midpoint between two points on a graph can have a negative x-value, a negative y-value, or both negative.