It would be nice if you could clarify exactly what you're trying to find, but I'll give it my educated guess.
Isolate 'y' from everything else first to put it into slope-intercept form.
$${\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{y}} = {\mathtt{1}}$$
$${\mathtt{\,-\,}}\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{y}}\right) = {\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}$$
$${\mathtt{y}} = {\frac{{\mathtt{3}}}{{\mathtt{4}}}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{4}}}}$$
The slope is 3/4 and the y-intercept is -1/4
Now, just plug it in to check!
$${\frac{{\mathtt{3}}}{{\mathtt{4}}}}{\mathtt{\,\times\,}}\left({\mathtt{5}}\right){\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{4}}}} = {\frac{{\mathtt{7}}}{{\mathtt{2}}}} = {\mathtt{3.5}}$$
Since the point (5,8) does not work with the equatino, (5,8) is not a point on the line.