Melody

So do you still want help or not?

hint

The roots will be at       $x = {-b \pm \sqrt{b^2-4ac} \over 2a}$

the axis of symentry will be the half way point between these roots.  

What will that be, as fa as the formula is concerned ?  

Sketch it if you are confused.  

the vertex is on the axis of symmetry.  so x=-4

Try taking it from here.

You have to lable the 3 sides first 

This site could help you

counter example

f(x)=x-2

g(x)=x^2-4

$\displaystyle \lim_{x\rightarrow2}\;f(x)=2-2=0\\ \displaystyle \lim_{x\rightarrow2}\;g(x)=2^2-4=0\\ \displaystyle \lim_{x\rightarrow2}\;(f \circ g)(x)= \lim_{x\rightarrow2}\;( x^2-4-2 )= -2\\ \displaystyle \lim_{x\rightarrow2}\;(g \circ f)(x)= \lim_{x\rightarrow2}\;( (x-2)^2-4 )= -4\\$

(0,0,0) is the centre of this space. It is a sphere of radius 1.

So it seems to me that that P(x+y+z<=0) = 0.5       That is just a guess. I can't claim to be sure.

You are both right           the answer is   100 base15   which is  225 base10

Answered on the original.

Just doing the substitutions.

$h(14)=72+10*14-0.7*14^2\\ h(14)=72+140-137.2\\ =74.8$

$27A=1(mod29)\\ 27A=-29N+1\\ 29N+27A=1\\~\\ 29=1(27)+2\\ 27=13(2)+1\\ 27-13(2)=1\\ 27-13(29-1(27))=1\\ 27-13(29)+13(27)=1\\ 14(27)-13(29)=1\\ 27*14=1(mod29)\\ $

So the modular inverse of 27 mod 29 is 14

Happy birthday!

Don't eat it all at once!