Melody

Fri 24/10/14

1) This simultaneous equations question was different - I liked it 

ok lets think about this

$$\\a^2+ab = 15 \qquad (1a)\\
a(a+b)=15 \qquad (1b)\\
a=\frac{15}{a+b} \qquad\qquad (1c)\\\\\\
2b^2 = 20 - 2ab\qquad (2a)\\
b^2=10-ab\qquad (2b)\\
b^2+ab=10\qquad (2c)\\
b(b+a)=10\qquad (2d)\\
b=\frac{10}{b+a}\qquad\qquad(2e)\\$$

So if

$$\\If\;\;a+b=35\;\;then\;\;a=15/35\;\;and\;\; b=10/35\\\\
If\;\;a+b=25\;\;then\;\;a=15/25\;\;and\;\; b=10/25\\\\
If\;\;a+b=-25\;\;then\;\;a=-15/25\;\;and\;\; b=-10/25\\\\
If\;\;a+b=-5\;\;then\;\;a=-15/5\;\;and\;\; b=-10/5\\\\
simplifying\;\; each \;\;of \;\;these\\\\\\
If\;\;a+b=35\;\;then\;\;a=3/7\;\;and\;\; b=2/7\\
BUT\qquad 3/7+2/7\ne35\;\; So\;\; no\;\; good\\\\
If\;\;a+b=25\;\;then\;\;a=3/5\;\;and\;\; b=2/5\\
BUT\qquad 3/5+2/5\ne25\;\; So\;\; no\;\; good\\\\
If\;\;a+b=-25\;\;then\;\;a=-3/5\;\;and\;\; b=-2/5\\
BUT\qquad -3/5+-2/5\ne-25\;\; So\;\; no\;\; good\\\\
If\;\;a+b=-5\;\;then\;\;a=-3\;\;and\;\; b=-2\\
AND\qquad -3+-2=-5\;\; So\;\; this\;\;answer\;\;is\;\; good\\\\$$

So a+b could be worth -5

yes is he walking or traveling by jet?

Please present you question better - I cannot be bothered with all that scrolling. 

since your question has not been answered i assume I am notthe only one that feels this way.

$$16+3x(-5)=16-15x$$

$$=576y+\frac{y}{99}$$

This question makes no sense. 

I like Geno's answer too Chris.

I think the question can be interpreted either way.  

Logs can be any base  (integers I think)

eg

$$y=log_381$$

this means

$$81=3^y$$

3*3*3*3=81

so

y=4

The calculator only works in base 10 and base e but it is easy to convoret other bases to either of these.

I wouldn't feel 'kept' if you gave me roses and even if I did who cares.  

'Kept' actually sounds kinda nurturing.

Sucking up always works for me.